Numpy数据类型对象报错:Future warning: _np_qint8 = np.dtype([("qint8", np.int8, 1)])

本文针对使用Python3.5.2环境下,通过pip安装Numpy后出现的dtype.py错误进行了详细解析。错误主要源于不推荐的dtype参数用法,未来版本的Numpy将改变其解释方式。文章提供了具体的修改方案,即将(np.int8,1)更改为(np.int8,(1,)),以符合Numpy的更新规范。

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我使用的是Python3.5.2,使用python的pip安装的Numpy结果dtype.py有以下错误

错误信息打印:FutureWarning: Passing (type, 1) or '1type' as a synonym of type is deprecated; in a future version of numpy, it will be understood as (type, (1,)) / '(1,)type'    _np_qint8 = np.dtype([("qint8", np.int8, 1)])

翻译:不推荐使用(type,1)或'1type'作为类型的同义词; 在未来的numpy版本中,它将被理解为(type,(1,))/'(1,)type'。 _np_qint8 = np.dtype([(“qint8”,np.int8,1)])
解决:改成 _np_qint8 = np.dtype([(“qint8”,np.int8,(1,)])

W:\Anaconda\envs\tensorflow\lib\site-packages\tensorflow\python\framework\dtypes.py:516: FutureWarning: Passing (type, 1) or '1type' as a synonym of type is deprecated; in a future version of numpy, it will be understood as (type, (1,)) / '(1,)type'. _np_qint8 = np.dtype([("qint8", np.int8, 1)]) W:\Anaconda\envs\tensorflow\lib\site-packages\tensorflow\python\framework\dtypes.py:517: FutureWarning: Passing (type, 1) or '1type' as a synonym of type is deprecated; in a future version of numpy, it will be understood as (type, (1,)) / '(1,)type'. _np_quint8 = np.dtype([("quint8", np.uint8, 1)]) W:\Anaconda\envs\tensorflow\lib\site-packages\tensorflow\python\framework\dtypes.py:518: FutureWarning: Passing (type, 1) or '1type' as a synonym of type is deprecated; in a future version of numpy, it will be understood as (type, (1,)) / '(1,)type'. _np_qint16 = np.dtype([("qint16", np.int16, 1)]) W:\Anaconda\envs\tensorflow\lib\site-packages\tensorflow\python\framework\dtypes.py:519: FutureWarning: Passing (type, 1) or '1type' as a synonym of type is deprecated; in a future version of numpy, it will be understood as (type, (1,)) / '(1,)type'. _np_quint16 = np.dtype([("quint16", np.uint16, 1)]) W:\Anaconda\envs\tensorflow\lib\site-packages\tensorflow\python\framework\dtypes.py:520: FutureWarning: Passing (type, 1) or '1type' as a synonym of type is deprecated; in a future version of numpy, it will be understood as (type, (1,)) / '(1,)type'. _np_qint32 = np.dtype([("qint32", np.int32, 1)]) W:\Anaconda\envs\tensorflow\lib\site-packages\tensorflow\python\framework\dtypes.py:525: FutureWarning: Passing (type, 1) or '1type' as a synonym of type is deprecated; in a future version of numpy, it will be understood as (type, (1,)) / '(1,)type'. np_resource = np.dtype([("resource", np.ubyte, 1)]) W:\Anaconda\envs\tensorflow\lib\site-packages\tensorboard\compat\tensorflow_stub\dtypes.py:541: FutureWarning: Passing (type, 1) or '1type' as a synonym of type is deprecated; in a futu
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03-14
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