1022. Digital Library (30)

本文介绍了一个基于图书信息的检索系统实现方法,该系统能够根据读者提供的查询条件(如书名、作者、关键词等)返回相应的图书,并按图书ID升序排列结果。文中详细解释了输入输出规范及系统实现细节。

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A Digital Library contains millions of books, stored according to their titles, authors, key words of their abstracts, publishers, and published years.  Each book is assigned an unique 7-digit number as its ID.  Given any query from a reader, you are supposed to output the resulting books, sorted in increasing order of their ID's.

Input Specification:

Each input file contains one test case.  For each case, the first line contains a positive integer N (<=10000) which is the total number of books.  Then N blocks follow, each contains the information of a book in 6 lines:

  • Line #1: the 7-digit ID number;
  • Line #2: the book title -- a string of no more than 80 characters;
  • Line #3: the author -- a string of no more than 80 characters;
  • Line #4: the key words -- each word is a string of no more than 10 characters without any white space, and the keywords are separated by exactly one space;
  • Line #5: the publisher  -- a string of no more than 80 characters;
  • Line #6: the published year -- a 4-digit number which is in the range [1000, 3000].

It is assumed that each book belongs to one author only, and contains no more than 5 key words; there are no more than 1000 distinct key words in total; and there are no more than 1000 distinct publishers.

After the book information, there is a line containing a positive integer M (<=1000) which is the number of user's search queries.  Then M lines follow, each in one of the formats shown below:

  • 1: a book title
  • 2: name of an author
  • 3: a key word
  • 4: name of a publisher
  • 5: a 4-digit number representing the year

Output Specification:

For each query, first print the original query in a line, then output the resulting book ID's in increasing order, each occupying a line.  If no book is found, print "Not Found" instead.

Sample Input:
3
1111111
The Testing Book
Yue Chen
test code debug sort keywords
ZUCS Print
2011
3333333
Another Testing Book
Yue Chen
test code sort keywords
ZUCS Print2
2012
2222222
The Testing Book
CYLL
keywords debug book
ZUCS Print2
2011
6
1: The Testing Book
2: Yue Chen
3: keywords
4: ZUCS Print
5: 2011
3: blablabla
Sample Output:
1: The Testing Book
1111111
2222222
2: Yue Chen
1111111
3333333
3: keywords
1111111
2222222
3333333
4: ZUCS Print
1111111
5: 2011
1111111
2222222
3: blablabla
Not Found

 注意点:因为时间的要求不高,所以id这个属性设置成string类型比较好,防止像000001用int表示就成为了1,格式不对了!

注意了 用getline()前如果用了cin流,则必须想用getline(cin,temp)来获取流当中的回车符!!!

简单的排序查找问题

AC参考代码:

#include <iostream>
#include <fstream>
#include <vector>
#include <algorithm>
using namespace std;
struct Node{
    string id;
    string bookname;
    string author;
    string keyword;
    string publisher;
    string year;
};
int compare(string s1,string s2){
    return s1<s2;
}
Node arr[10001];
int N,M;
int main()
{
    //ifstream cin("1.txt");
    cin>>N;
    string temp;
    getline(cin,temp);
    for(int i=0;i<N;i++){
        getline(cin,arr[i].id);
        getline(cin,arr[i].bookname);
        getline(cin,arr[i].author);
        getline(cin,arr[i].keyword);
        getline(cin,arr[i].publisher);
        getline(cin,arr[i].year);
    }
    cin>>M;
    //cout<<M<<endl;
    getline(cin,temp);
    for(int i=0;i<M;i++){
        string s;
        getline(cin,s);
        cout<<s<<endl;
        char ch = s[0];
        s = s.substr(3,s.size());
        if(ch=='1'){    //bookname
            vector<string> idArr;
            for(int j=0;j<N;j++){
                if(arr[j].bookname==s){
                    idArr.push_back(arr[j].id);
                }
            }
            if(idArr.size()==0){
                cout<<"Not Found"<<endl;
                continue;
            }
            sort(idArr.begin(),idArr.end(),compare);
            for(int j=0;j<idArr.size();j++){
                cout<<idArr[j]<<endl;
            }
        }
        if(ch=='2'){  //author
           vector<string> authorArr;
           for(int j=0;j<N;j++){
                if(arr[j].author==s){
                    authorArr.push_back(arr[j].id);
                }
           }
           if(authorArr.size()==0){
                cout<<"Not Found"<<endl;
                continue;
           }
           sort(authorArr.begin(),authorArr.end(),compare);
           for(int j=0;j<authorArr.size();j++){
                cout<<authorArr[j]<<endl;
           }
        }
        if(ch=='3'){  //author
           vector<string> keywordArr;
           for(int j=0;j<N;j++){
                if(arr[j].keyword.find(s)<100){
                    keywordArr.push_back(arr[j].id);
                }
           }
           if(keywordArr.size()==0){
            cout<<"Not Found"<<endl;
            continue;
           }
           sort(keywordArr.begin(),keywordArr.end(),compare);
           for(int j=0;j<keywordArr.size();j++){
            cout<<keywordArr[j]<<endl;
           }
        }
        if(ch=='4'){    //publisher
            vector<string> publisherArr;
            for(int j=0;j<N;j++){
                if(arr[j].publisher==s){
                    publisherArr.push_back(arr[j].id);
                }
           }
           if(publisherArr.size()==0){
                cout<<"Not Found"<<endl;
                continue;
           }
           sort(publisherArr.begin(),publisherArr.end(),compare);
           for(int j=0;j<publisherArr.size();j++){
                cout<<publisherArr[j]<<endl;
           }
        }
        if(ch=='5'){    //year
            vector<string> yearArr;
            for(int j=0;j<N;j++){
                if(arr[j].year==s){
                    yearArr.push_back(arr[j].id);
                }
           }
           if(yearArr.size()==0){
                cout<<"Not Found"<<endl;
                continue;
           }
           sort(yearArr.begin(),yearArr.end(),compare);
           for(int j=0;j<yearArr.size();j++){
                cout<<yearArr[j]<<endl;
           }
        }
    }
    return 0;
}


 

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