1048. Find Coins (25)

最新推荐文章于 2024-02-20 17:56:40 发布

原创最新推荐文章于 2024-02-20 17:56:40 发布 · 375 阅读

0 ·

CC 4.0 BY-SA版权

PAT 专栏收录该内容

79 篇文章

订阅专栏

本文介绍了一个支付场景下的问题——FindCoins。在这个问题中，需要从大量不同面额的硬币中找出两个硬币来支付特定金额。文章详细阐述了如何通过编程解决这一问题，并给出了具体的代码实现。

1048. Find Coins (25)

Eva loves to collect coins from all over the universe, including some other planets like Mars. One day she visited a universal shopping mall which could accept all kinds of coins as payments. However, there was a special requirement of the payment: for each bill, she could only use exactly two coins to pay the exact amount. Since she has as many as 10⁵ coins with her, she definitely needs your help. You are supposed to tell her, for any given amount of money, whether or not she can find two coins to pay for it.

Input Specification:

Each input file contains one test case. For each case, the first line contains 2 positive numbers: N (<=10⁵, the total number of coins) and M(<=10³, the amount of money Eva has to pay). The second line contains N face values of the coins, which are all positive numbers no more than 500. All the numbers in a line are separated by a space.

Output Specification:

For each test case, print in one line the two face values V₁ and V₂ (separated by a space) such that V₁ + V₂ = M and V₁ <= V₂. If such a solution is not unique, output the one with the smallest V₁. If there is no solution, output "No Solution" instead.

Sample Input 1:

8 15
1 2 8 7 2 4 11 15

Sample Output 1:

4 11

Sample Input 2:

7 14
1 8 7 2 4 11 15

Sample Output 2:

No Solution

注意coin的两个值相等的情况！

参考代码：

#include <iostream>
#include <vector>
#include <stdio.h>
using namespace std;
vector<int> arr(100001);
int N,M;
int main()
{
    scanf("%d%d",&N,&M);
    for(int i=0;i<N;i++){
        int temp;
        scanf("%d",&temp);
        arr[temp]++;
    }
    for(int i=1;i<=M;i++){
        if(arr[i]>0){
            if(arr[M-i]>0){
                if(2*i!=M){
                    cout<<i<<" "<<M-i;
                    return 0;
                }else if(arr[i]>1){
                    cout<<i<<" "<<i;
                    return 0;
                }
            }
        }
    }
    cout<<"No Solution";
    return 0;
}