Write an algorithm to determine if a number is "happy".
A happy number is a number defined by the following process: Starting with any positive integer, replace the number by the sum of the squares of its digits, and repeat the process until the number equals 1 (where it will stay), or it loops endlessly in a cycle which does not include 1. Those numbers for which this process ends in 1 are happy numbers.
Example: 19 is a happy number
- 12 + 92 = 82
- 82 + 22 = 68
- 62 + 82 = 100
- 12 + 02 + 02 = 1
思路:就是循环到n<10为止,在这过程中,把n拆分运算
代码如下(已通过leetcode)
public class Solution {
public boolean isHappy(int n) {
List<Integer> list=new ArrayList<Integer>();
list.add(n);
int temp=n;
boolean isrepeate=false;
while(temp>0) {
if(isrepeate) break;
String strn=""+temp;
temp=0;
int length=strn.length();
for(int i=0;i<length;i++) {
temp+=(strn.charAt(i)-'0')*(strn.charAt(i)-'0');
}
Iterator<Integer> it=list.iterator();
while(it.hasNext()) {
if(temp==it.next()) {
if(temp==1) return true;
else {
isrepeate=true;
break;
}
}
}
if(!isrepeate) list.add(temp);
}
return false;
}
}