Write a function that takes an unsigned integer and returns the number of ’1' bits it has (also known as the Hamming weight).
For example, the 32-bit integer ’11' has binary representation 00000000000000000000000000001011
, so the function should return 3.
思路:因为是32位的,循环32次,n&1==1时,count++,n>>1;
代码如下(已通过leetcode)
public class Solution {
// you need to treat n as an unsigned value
public int hammingWeight(int n) {
String str=Integer.toBinaryString(n);
//System.out.println(str);
int count=0;
for(int i=0;i<str.length();i++) {
if(str.charAt(i)=='1') count++;
}
return count;
}
}