There are N gas stations along a circular route, where the amount of gas at station
i is
gas[i]
.
You have a car with an unlimited gas tank and it costs cost[i]
of gas to travel from station
i to its next station (i+1). You begin the journey with an empty tank at one of the gas stations.
Return the starting gas station's index if you can travel around the circuit once, otherwise return -1.
Note:
The solution is guaranteed to be unique.
class Solution {
public:
int canCompleteCircuit(vector<int> &gas, vector<int> &cost) {
// Note: The Solution object is instantiated only once and is reused by each test case.
vector<int> merge;
int curGas = 0;
int curPos = 0;
int beginPos = 0;
int lenRound = gas.size();
for (int i=0; i<lenRound; i++)
{
merge.push_back(gas[i]-cost[i]);
}
curGas = 0;
curPos = 0;
for (int beginPos=0; beginPos<lenRound;)
{
while (curGas>=0 && curPos<beginPos+lenRound)
{
curGas += merge[(curPos++)%lenRound];
}
if (curGas>=0 && curPos==beginPos+lenRound)
{
return beginPos;
}
curGas -= merge[beginPos];
beginPos++;
}
return -1;
}
};