leetcode combine sum I
Given a set of candidate numbers (C) and a target number (T), find all unique combinations in C where the candidate numbers sums to T.
The same repeated number may be chosen from C unlimited number of times.
Note:
- All numbers (including target) will be positive integers.
- Elements in a combination (a1, a2, … , ak) must be in non-descending order. (ie, a1 ≤ a2 ≤ … ≤ ak).
- The solution set must not contain duplicate combinations.
For example, given candidate set 2,3,6,7
and target 7
,
A solution set is:
[7]
[2, 2, 3]
public class Solution {
public ArrayList<ArrayList<Integer>> combinationSum(int[] candidates, int target) {if(candidates==null||candidates.length==0) return null;
Arrays.sort(candidates);
ArrayList<ArrayList<Integer>> res = new ArrayList<ArrayList<Integer>>();
helper(res, candidates, target, new ArrayList<Integer>(), 0);
return res;
}
private void helper(ArrayList<ArrayList<Integer>> res, int[] cand, int target, ArrayList<Integer> item, int start){
if(target<0) return;
if(target==0){
res.add(new ArrayList<Integer> (item)); //think why must add new here ?? 除了基本8种data types,http://docs.oracle.com/javase/tutorial/java/nutsandbolts/datatypes.html, 其他java里的类型都是指针,此处传入的item为指针, 在之后的引用中变化了,所以如果不new 一个新的copy,会在这里也被错误的变化了
}
for(int i=start;i<cand.length;i++){
if(i>start && cand[i]==cand[i-1]) continue; // which means this candidate has been examined;
item.add(cand[i]);
helper(res, cand, target-cand[i], item, i);
item.remove(item.size()-1);
}
}
}
Combination Sum II
Given a collection of candidate numbers (C) and a target number (T), find all unique combinations in C where the candidate numbers sums to T.
Each number in C may only be used once in the combination.
Note:
- All numbers (including target) will be positive integers.
- Elements in a combination (a1, a2, … , ak) must be in non-descending order. (ie, a1 ≤ a2 ≤ … ≤ ak).
- The solution set must not contain duplicate combinations.
For example, given candidate set 10,1,2,7,6,1,5
and
target 8
,
A solution set is:
[1, 7]
[1, 2, 5]
[2, 6]
[1, 1, 6]
public class Solution {
public ArrayList<ArrayList<Integer>> combinationSum2(int[] num, int target) {
ArrayList<ArrayList<Integer>> res = new ArrayList<ArrayList<Integer>>();
if(num.length==0||num==null) return res;
Arrays.sort(num);
helper(0, num, target, res, new ArrayList<Integer>());
return res;
}
private void helper(int start, int[] num, int target, ArrayList<ArrayList<Integer>> res,ArrayList<Integer> item){
if(target<0) {
return;
}
if(target==0){
res.add(new ArrayList<Integer>(item));
return;
}
for(int i=start;i<num.length;i++){
if(i>start&&num[i]==num[i-1]) continue;
item.add(num[i]);
helper(i+1,num,target-num[i], res,item);
item.remove(item.size()-1);
}
}
}