SpringBoot中如何上传Upload

最新推荐文章于 2025-04-09 11:00:00 发布

原创最新推荐文章于 2025-04-09 11:00:00 发布 · 792 阅读

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#SpringBoot #SpringBoot 上传Upload #MultipartFile #马克java社区

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马克-to-win@马克java社区：根据第3部分的helloworld例子，用那个项目做底子。pom.xml都不用改变。参考项目bootUpload1.

static/index.html:

<!DOCTYPE html>
<html>
<head>
<meta charset="UTF-8">
<title>Insert title here</title>
</head>
<body>
index1

<form method="POST" action="/upload" enctype="multipart/form-data">
    <input type="file" name="file" /><br/><br/>
    <input type="submit" value="Submit" />
</form>
</body>
</html>

package com.SpringbootMaven;

import org.springframework.stereotype.Controller;
import org.springframework.web.bind.annotation.RequestMapping;
import org.springframework.web.bind.annotation.RequestParam;
import org.springframework.web.multipart.MultipartFile;
import java.io.IOException;
import java.nio.file.Files;
import java.nio.file.Path;
import java.nio.file.Paths;
import javax.servlet.http.HttpServletResponse;

@Controller
public class UploadController {
    private static String UPLOADED_FOLDER = "e://temp//";

    @RequestMapping("/upload")
    public void singleFileUpload(@RequestParam("file") MultipartFile file,HttpServletResponse res) throws IOException {
        try {
            byte[] bytes = file.getBytes();
            Path path = Paths.get(UPLOADED_FOLDER + file.getOriginalFilename());
            Files.write(path, bytes);
            System.out.println("马克-to-win@马克java社区 successfully");
        } catch (IOException e) {
            e.printStackTrace();
        }
        res.sendRedirect("index.html");
    }
}