informix计算时间相差
select t.insert_time,((t.clear_time-t.insert_time)::interval second(9) to second ::char(20) ::integer),extend(t.clear_time, year to second) from tab1 t 获得的第二个值是字段clear_time,insert_time相差的秒数,秒数差太大可...
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2018-08-13 10:40:06 ·
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