93. Restore IP Addresses (M)

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Restore IP Addresses (M)

Given a string containing only digits, restore it by returning all possible valid IP address combinations.

Example:

Input: "25525511135"
Output: ["255.255.11.135", "255.255.111.35"]

题意

解析一段字符串,返回所有能构成有效IP地址的组合。

思路

有效的IP地址由四节组成,每一节的数字最多有三位且该数字不大于255,有多位的数字起始不能为0。

利用回溯法进行处理。


代码实现

class Solution {
    public List<String> restoreIpAddresses(String s) {
        List<String> ans = new ArrayList<>();
        if (s.length() > 12 || s.length() < 4) {
            return ans;
        }
        dfs(s, 0, new StringBuilder(), 0, ans);
        return ans;
    }

    private void dfs(String s, int pos, StringBuilder sb, int size, List<String> ans) {
        if (pos == s.length() && size == 4) {
            ans.add(sb.toString());
            return;
        } else if (size == 4) {
            // 如果已经有四节,但还有字符没处理
            return;
        }

        for (int i = 1; i <= 3; i++) {
            if (pos + i > s.length() || i > 1 && s.charAt(pos) == '0') {
                break;
            }
            String t = s.substring(pos, pos + i);
            if (Integer.parseInt(t) <= 255) {
                t = pos == 0 ? t : '.' + t;
                sb.append(t);
                dfs(s, pos + i, sb, size + 1, ans);
                sb.delete(sb.length() - t.length(), sb.length());
            }
        }
    }
}
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