Binary Tree Zigzag Level Order Traversal (M)
Given a binary tree, return the zigzag level order traversal of its nodes’ values. (ie, from left to right, then right to left for the next level and alternate between).
For example:
Given binary tree [3,9,20,null,null,15,7],
3
/ \
9 20
/ \
15 7
return its zigzag level order traversal as:
[
[3],
[20,9],
[15,7]
]
题意
按从上到下的顺序记录二叉树的每一层,但每一层的左右顺序与上一层相反。
思路
BFS,如果为偶数层则将该层的序列逆置。
代码实现
/**
* Definition for a binary tree node.
* public class TreeNode {
* int val;
* TreeNode left;
* TreeNode right;
* TreeNode(int x) { val = x; }
* }
*/
class Solution {
public List<List<Integer>> zigzagLevelOrder(TreeNode root) {
List<List<Integer>> ans = new ArrayList<>();
Queue<TreeNode> q = new ArrayDeque<>();
int level = 0;
if (root != null) {
q.offer(root);
}
while (!q.isEmpty()) {
level++;
List<Integer> list = new ArrayList<>();
int size = q.size();
for (int i = 0; i < size; i++) {
TreeNode cur = q.poll();
list.add(cur.val);
if (cur.left!=null) q.offer(cur.left);
if (cur.right!=null) q.offer(cur.right);
}
if (level % 2 == 0) {
Collections.reverse(list);
}
ans.add(list);
}
return ans;
}
}
本文介绍了一种二叉树的特殊遍历方式——锯齿形层序遍历,即从左到右再从右到左交替进行。通过广度优先搜索(BFS)算法,并在偶数层时反转节点值的顺序,实现了这一遍历过程。
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