acm hnu 10049 IP Address

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本文介绍了一种将32位二进制IP地址转换为十进制点分表示法的方法，并提供了一个简单的C语言实现示例。

IP Address

Time Limit: 1000ms, Special Time Limit:2500ms, Memory Limit:32768KB

Total submit users: 254, Accepted users: 239

Problem 10049 : No special judgement

Problem description

Suppose you are reading byte streams from any device, representing IP addresses. Your task is to convert a 32 characters long sequence of '1s' and '0s' (bits) to a dotted decimal format. A dotted decimal format for an IP address is form by grouping 8 bits at a time and converting the binary representation to decimal representation. Any 8 bits is a valid part of an IP address. To convert binary numbers to decimal numbers remember that both are positional numerical systems, where the first 8 positions of the binary systems are:

27 26 25 24 23 22 21 20 128 64 32 16 8 4 2 1

Input

The input will have a number N (1<=N<=9) in its first line representing the number of streams to convert. N lines will follow.

Output

The output must have N lines with a doted decimal IP address. A dotted decimal IP address is formed by grouping 8 bit at the time and converting the binary representation to decimal representation.

Sample Input

4
00000000000000000000000000000000 
00000011100000001111111111111111 
11001011100001001110010110000000 
01010000000100000000000000000001

Sample Output

0.0.0.0
3.128.255.255
203.132.229.128
80.16.0.1

Problem Source

MCA 2004

code:

/*start 17:43*/
/*end 18:08  25min*/
#include <stdio.h>
#include <string.h>

main()
{
      int n,i,j,p,dec=0;
      char s[32];
      scanf("%d",&n);

      for( i = 0 ; i < n ; i++ ){
           scanf("%s",s);
           for( j = 0,p = 7 ; j < 32 ; j++,p--){


                    if(s[j]=='1')dec+=pow(2,p);
                    if( p == 0 ){
                        p=8;
                        printf("%d",dec);
                        dec=0;
                        if(j == 31)printf(" ");
                        else printf(".");
                    }


           }
      }

      system("PAUSE");
}