[Leetcode] 796. Rotate String 解题报告

最新推荐文章于 2020-12-15 21:08:52 发布

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本文介绍了一个简单的算法问题，即判断通过若干次将字符串A的最左字符移至最右位置的操作能否使A变为字符串B。文章提供了C++实现的示例代码。

题目：

We are given two strings, A and B.

A shift on A consists of taking string A and moving the leftmost character to the rightmost position. For example, if A = 'abcde', then it will be 'bcdea' after one shift on A. Return True if and only if A can become B after some number of shifts on A.

Example 1:
Input: A = 'abcde', B = 'cdeab'
Output: true

Example 2:
Input: A = 'abcde', B = 'abced'
Output: false

Note:

A and B will have length at most 100.

思路：

练手题目，哈哈。

代码：

class Solution {
public:
    bool rotateString(string A, string B) {
        if (A.length() != B.length()) {
            return false;
        }
        if (A == B) {
            return true;
        }
        for (int i = 0; i + 1 < A.length(); ++i) {
            A.push_back(A[0]);     // move the first char to the back
            A.erase(A.begin());
            if (A == B) {
                return true;
            }
        }
        return false;
    }
};