编写一个数组求和函数void Add(int n, int* a1, int* a2, int* result); 其中n<100是数组长度,a1是第一个数组,a2是第二个数组,result是a1和a2的和。假设a1={2, 4, 5, 8}, a2={1, 0, 4, 6},则result={3, 4, 9, 14};
编写main函数测试该函数的正确性。依次输入n, a1, a2, 输出result。
输入: 4 2 4 5 8 1 0 4 6
输出:
3 4 9 14
import java.util.Arrays;
import java.util.Scanner;
public class Main {
public static void main(String[] args) {
Scanner sc= new Scanner(System.in);
int n = sc.nextInt();
int[] a1= new int [n];
int[] a2= new int [n];
int[] result=new int [n];
for (int i = 0; i < n; i++) {
a1[i]=sc.nextInt();
}
for (int i = 0; i < n; i++) {
a2[i]=sc.nextInt();
}
for (int i = 0; i <n; i++) {
result[i]=a1[i]+a2[i];
}
for(int i=0;i<n;i++)
{
System.out.print(result[i]+" ");
}
}
}