1.请编程实现哈希表的创建存储数组{12,24,234,234,23,234,23},输入key查找的值,实现查找功能
#include<stdio.h>
#include<string.h>
#include<stdlib.h>
#include<math.h>
typedef int datatype;
typedef struct Node
{
datatype data;
struct Node *next;
}*node;
int prime(int m)
{
for(int i=m;i>=2;i--)
{
int flag=0;
for(int j=2;j<sqrt(m);j++)
{
if(i%j==0)
{
flag=-1;
break;
}
}
if(flag==0)
return i;
}
}
node create()
{
node s=(node)malloc(sizeof(struct Node));
if(s==NULL)
return NULL;
s->data=0;
s->next=NULL;
return s;
}
void insert_hash(int key,node hash[],int p)
{
int index=key%p;
node s=create();
s->data=key;
if(hash[index]==NULL)
hash[index]=s;
else
{
s->next=hash[index];
hash[index]=s;
}
}
void output(node hash[],int m)
{
for(int i=0;i<m;i++)
{
printf("%d:",i);
node p=hash[i];
while(p)
{
printf("%-5d",p->data);
p=p->next;
}
puts("");
}
}
int search_key(node hash[],int p,int key)
{
int index=key%p;
node head=hash[index];
while(head!=NULL)
{
if(key==head->data)
return 0;
head=head->next;
}
return -1;
}
int main(int argc, const char *argv[])
{
int arr[]={12,24,234,234,23,234,23};
int len=sizeof(arr)/sizeof(arr[0]);
int m=len*4/3;//计算哈希表的长度
node hash[m];//定义哈希表
for(int i=0;i<m;i++)
hash[i]=NULL;
int p=prime(m);
for(int i=0;i<len;i++)//把数组元素存到哈希表中
{
insert_hash(arr[i],hash,p);
}
//输出哈希表
output(hash,m);
//查找
int key;
printf("please enter the key:");
scanf("%d",&key);
int flag=search_key(hash,p,key);
if(flag==0)
puts("exist");
if(flag==-1)
puts("unexist");
return 0;
}
2.现有数组{12,23,45,56,445,5676,6888],请输入key实现二分查找
#include<stdio.h>
#include<string.h>
#include<stdlib.h>
int half_search(int arr[],int key,int len,int low,int high)
{
while(low<=high)
{
int m=(low+high)/2;
if(key>arr[m])
{
low=m+1;
}
else if(key==arr[m])
{
return m;
}
else
{
high=m-1;
}
}
return -1;
}
int main(int argc, const char *argv[])
{
int arr[]={12,23,45,56,445,5676,6888};
int len=sizeof(arr)/sizeof(arr[0]);
int low=1;
int high=len;
int key;
printf("please enter the search key:");
scanf("%d",&key);
int index=half_search(arr,key,len,low,high);
printf("the search index:%d\n",index);
return 0;
}