#include <stdio.h>
int main()
{
int n;
scanf("%d", &n );
int arr[n][n];
int i,j;
for ( i = 0; i < n; i++ ) {
for ( j = 0; j < n; j++ ) {
scanf("%d", &arr[i][j]);
}
}
int row = 0, column = 0, k;
int flog = 0;
for ( i = 0; i < n; i++ ) {
for ( j = 0; j < n; j++ ) {
if ( column == j ) continue;
else if (arr[i][column] < arr[i][j] )
column = j;
}
for ( k = 0; k < n; k++ ) {
if ( row == k ) continue;
else if (arr[row][column] > arr[k][column])//判断它是最小的
row = k;
}
if (row == i ){
flog = 1;
break;
}
}
if(flog == 1 )
printf("%d %d\n", row, column );
else
printf("NO");
return 0;
}
求二维整型数组的“鞍点“。二维数组的“鞍点“定义为:某个数是所在行的最大值,并且是所在列的最小值。
最新推荐文章于 2024-01-05 10:15:29 发布