稀疏数组
当一个数组中大部分元素为0,或者为同一值的数组时,可以使用稀疏数组来保存该数组。
稀疏数组的处理方式是:
记录数组一共有几行几列,有多少个不同值
把具有不同值的元素和行列及值记录在一个小规模的数组中,从 而缩小程序的规模
如下图:
左边是原始数组,右边是稀疏数组
应用
创建一个11*11的数组,0:没有数组,1:黑棋,2:白棋
public class SparseArray { public static void main(String[] args) { //创建一个11*11的数组,0:没有数组,1:黑棋,2:白棋 int[][] a = new int[11][11]; a[1][2] = 1; a[2][3] = 2; //输出数组 for(int i =0; i < 11; i++){ for(int j = 0; j < 11; j++){ System.out.print(a[i][j]+"\t"); } System.out.println(); } } }
将数组转为稀疏数组
public static void main(String[] args) { //创建一个11*11的数组,0:没有数组,1:黑棋,2:白棋 int[][] a = new int[11][11]; a[1][2] = 1; a[2][3] = 2; //输出数组 for (int i = 0; i < 11; i++) { for (int j = 0; j < 11; j++) { System.out.print(a[i][j] + "\t"); } System.out.println(); } //转为稀疏数组 System.out.println("稀疏数组:"); //读取有效值个数 int count = 0; for (int i = 0; i < 11; i++) { for (int j = 0; j < 11; j++) { if (a[i][j] != 0) { count++; } } } int[][] b = new int[count + 1][3]; //给稀疏矩阵赋值 b[0][0] = 11; b[0][1] = 11; b[0][2] = count; int sum = 0; for (int i = 0; i < 11; i++) { for (int j = 0; j < 11; j++) { if (a[i][j] != 0) { sum++; b[sum][0] = i; b[sum][1] = j; b[sum][2] = a[i][j]; } } } //输出稀疏数组 for (int i = 0; i < count+1; i++) { for (int j = 0; j < 3; j++) { System.out.print(b[i][j] + "\t"); } System.out.println(); } }
还原稀疏矩阵
/** * @author JenKinRJX * @create 2022-01-15-15:30 */ public class SparseArray { public static void main(String[] args) { //创建一个11*11的数组,0:没有数组,1:黑棋,2:白棋 int[][] a = new int[11][11]; a[1][2] = 1; a[2][3] = 2; //输出数组 for (int i = 0; i < 11; i++) { for (int j = 0; j < 11; j++) { System.out.print(a[i][j] + "\t"); } System.out.println(); } //转为稀疏数组 System.out.println("稀疏数组:"); //读取有效值个数 int count = 0; for (int i = 0; i < 11; i++) { for (int j = 0; j < 11; j++) { if (a[i][j] != 0) { count++; } } } int[][] b = new int[count + 1][3]; //给稀疏矩阵赋值 b[0][0] = 11; b[0][1] = 11; b[0][2] = count; int sum = 0; for (int i = 0; i < 11; i++) { for (int j = 0; j < 11; j++) { if (a[i][j] != 0) { sum++; b[sum][0] = i; b[sum][1] = j; b[sum][2] = a[i][j]; } } } //输出稀疏数组 for (int i = 0; i < count+1; i++) { for (int j = 0; j < 3; j++) { System.out.print(b[i][j] + "\t"); } System.out.println(); } System.out.println("还原稀疏矩阵:"); //还原稀疏矩阵 int[][] c = new int[b[0][0]][b[0][1]]; for(int i =1; i<count+1; i++){ c[b[i][0]][b[i][1]] = b[i][2]; } for(int i = 0; i<b[0][0]; i++){ for(int j =0; j<b[0][1];j++){ System.out.print(c[i][j]+"\t"); } System.out.println(); } } }
/** * @author JenKinRJX * @create 2022-01-15-15:30 */ public class SparseArray { public static void main(String[] args) { //创建一个11*11的数组,0:没有数组,1:黑棋,2:白棋 int[][] a = new int[11][11]; a[1][2] = 1; a[2][3] = 2; //输出数组 for (int i = 0; i < 11; i++) { for (int j = 0; j < 11; j++) { System.out.print(a[i][j] + "\t"); } System.out.println(); } //转为稀疏数组 System.out.println("稀疏数组:"); //读取有效值个数 int count = 0; for (int i = 0; i < 11; i++) { for (int j = 0; j < 11; j++) { if (a[i][j] != 0) { count++; } } } int[][] b = new int[count + 1][3]; //给稀疏矩阵赋值 b[0][0] = 11; b[0][1] = 11; b[0][2] = count; int sum = 0; for (int i = 0; i < 11; i++) { for (int j = 0; j < 11; j++) { if (a[i][j] != 0) { sum++; b[sum][0] = i; b[sum][1] = j; b[sum][2] = a[i][j]; } } } //输出稀疏数组 for (int i = 0; i < count+1; i++) { for (int j = 0; j < 3; j++) { System.out.print(b[i][j] + "\t"); } System.out.println(); } System.out.println("还原稀疏矩阵:"); //还原稀疏矩阵 int[][] c = new int[b[0][0]][b[0][1]]; for(int i =1; i<count+1; i++){ c[b[i][0]][b[i][1]] = b[i][2]; } for(int i = 0; i<b[0][0]; i++){ for(int j =0; j<b[0][1];j++){ System.out.print(c[i][j]+"\t"); } System.out.println(); } } }