#include <iostream>
#include <cstdio>
#include <cmath>
using namespace std;
int main()
{
int N[3000] = {1};
int m = 1;
int n;
cin >> n;
for (int i=0;i<n;i++)
{
int t = 0;
for (int j=0;j<m;j++)
{
t += N[j]*2;
N[j] = t%10;
t = t/10;
}
if (t == 1)
{
N[m++] = 1;
}
}
for (int i=m-1;i>=0;i--)
{
printf ("%d",N[i]);
}
return 0;
}