1.题目要求:
2.题目代码:
class Solution {
public:
int trainingPlan(vector<int>& actions) {
//设置multimap容器,记录每个元素的次数
multimap<int,int> array;
for(int i = 0;i < actions.size();i++){
multimap<int,int> :: iterator it = array.find(actions[i]);
if(it != array.end()){
it->second += 1;
}else{
array.insert(make_pair(actions[i],1));
}
}
//遍历multimap容器,找到出现次数为1的次数返回此元素
for(multimap<int,int>:: iterator it = array.begin();it != array.end();it++){
if(it->second == 1){
return it->first;
}
}
return 0;
}
};