1.数组去重
arr中有相同的数去掉
let arr = [1,2,3,4,5,4,3,2,1];
let result = [...new Set(arr)];
console.log(result);//1,2,3,4,5
2.交集
let arr = [1,2,3,4,5,4,3,2,1];
let arr2 = [4,5,6,5,6];
let result =[...new Set(arr)].filter(item => {
let s2=new Set(arr2);//[4·5.6]
if(s2.has(item)){
return true;
}else{
return false;
}
});
//let result =[...new Set(arr)].filter(item => new Set(arr2).has(item));
console.log(result);//[4,5]
3.并集
let arr = [1,2,3,4,5,4,3,2,1];
let arr2 = [4,5,6,5,6];
let union=[...new Set([...arr,...arr2])];
console.log(union)//[1,2,3,4,5,6]
4.差集
let arr = [1,2,3,4,5,4,3,2,1];
let arr2 = [4,5,6,5,6];
let diff=[...new Set(arr)].filter(item=>!(new Set(arr2).has(item)));
console.log(diff)//[1,2,3]