https://leetcode-cn.com/problems/implement-stack-using-queues/
题目描述
题解
- 使用一个队列实现即可
- 每次向队列中加入元素的时候,将队列中之前的元素全部出队列再入队列
- 这样最新入队列的元素,变成了第一个,第一个出队列。
后入先出
class MyStack {
Queue<Integer> queue = new LinkedList<Integer>();
/** Initialize your data structure here. */
public MyStack() {
}
/** Push element x onto stack. */
public void push(int x) {
int size = queue.size();
queue.offer(x);
// 将队列中原先存在的元素全部重新入一次队列
for(int i=0; i<size; i++){
queue.offer(queue.poll());
}
}
/** Removes the element on top of the stack and returns that element. */
public int pop() {
return queue.poll();
}
/** Get the top element. */
public int top() {
return queue.peek();
}
/** Returns whether the stack is empty. */
public boolean empty() {
return queue.isEmpty();
}
}
/**
* Your MyStack object will be instantiated and called as such:
* MyStack obj = new MyStack();
* obj.push(x);
* int param_2 = obj.pop();
* int param_3 = obj.top();
* boolean param_4 = obj.empty();
*/