//求循环节的位数
#include<vector>
#include<algorithm>
#include<iostream>
using namespace std;
int f(int n, int m)
{
vector<int> v;
n = n%m;
for(;;)
{
v.push_back(n);
n = n*10;
n = n%m;
if(n==0)
return 0;
if(find(v.begin(), v.end(), n) != v.end())
{
//在下面填入代码
return (int)( v.end() - find(v.begin(), v.end(), n));
}
}
}
int main()
{
int n, m;
cin >> n >> m;
cout << "n%m = " << n%m << endl << "n%m*10 = " << n%m*10 << endl << "n%m*10%m = " << n%m*10%m << endl;
cout << f(n, m) << endl;
return 0;
}