Problem:
Given a singly linked list L: L0→L1→…→Ln-1→Ln,
reorder it to: L0→Ln→L1→Ln-1→L2→Ln-2→…
You must do this in-place without altering the nodes' values.
For example,
Given {1,2,3,4}
, reorder it to {1,4,2,3}
.
/**
* Definition for singly-linked list.
* struct ListNode {
* int val;
* ListNode *next;
* ListNode(int x) : val(x), next(NULL) {}
* };
*/
class Solution {
public:
void reorderList(ListNode* head) {
if(!head || !head->next) return;
vector<ListNode*> list;
while(head){
list.push_back(head);
head = head->next;
}
int n = list.size();
for(int i = 0; i < n / 2; i++){
list[i]->next = list[n - i - 1];
list[n - i - 1]->next = list[i + 1];
}
list[n / 2]->next = NULL;
}
};