《python语言程序设计》2018版第8章第15题商业:检测ISBN-10一个国际标准书号

这个作者一天净出幺蛾子.我这边还老打错字,我现在都不敢用缩写,都是全拼

str_vis_text = "013601267"
len_num = len(str_vis_text)



def run_text(num_t, text_about):
    text_sum = 0
    for i in range(0, num_t):
        text_sum +=if_digit(text_about[i])*(i+1)
    print(text_sum%11)
    print(text_sum)

run_text(len_num, str_vis_text)

用excel计算的结果.

用python计算的结果

那么我直接把text_sum % 11变成运行代码不就成功了吗???

not all arguments converted during string formatting

差哪里呢??
天呐,我犯了一个问题
哈哈哈
应该是text_sum %11 可我写成了text_about % 11

修改后成功

def run_text(num_t, text_about):
    text_sum = 0
    for i in range(0, num_t):
        text_sum += if_digit(text_about[i]) * (i + 1)
    return text_sum % 11


a = str(run_text(len_num, str_vis_text))

print(str_vis_text + a)

结下来加个识别x的语句

最后成功的代码

def run_text(num_t, text_about):
    text_sum = 0
    for i in range(0, num_t):
        text_sum += if_digit(text_about[i]) * (i + 1)
    #这段代码不要放入到for循环里,注意缩紧
    if text_sum % 11 == 10:
        return "X"
    else:
        return text_sum % 11


a = str(run_text(len_num, str_vis_text))

print(str_vis_text + a)

str_vis_text = input("Enter the first 9 digits of an ISBN-10 as a string: ")
str_vis_text = "013601267"
str_vis_text = "013031997"

这3个名字大家自己选吧

忘了加if_digit的代码了

def if_digit(num):
    if num == "0":
        return 0
    elif num == "1":
        return 1
    elif num == "2":
        return 2
    elif num == "3":
        return 3
    elif num == "4":
        return 4
    elif num == "5":
        return 5
    elif num == "6":
        return 6
    elif num == "7":
        return 7
    elif num == "8":
        return 8
    elif num == "8":
        return 8
    elif num == "9":
        return 9