#include<iostream>
using namespace std;
int main()
{
int sum=0;
int year,month,day;
int a[12]={31,28,31,30,31,30,31,31,30,31,30,31};
cin>>year>>month>>day;
if(0==year%4&&(year%100)!=0||year%400==0)
{
a[1]=a[1]+1;
}
for(int i=0;i<month-1;i++)
{
sum+=a[i];
}
sum+=day;
cout<<sum<<endl;
return 0;
}
判断日期是一年的多少天
最新推荐文章于 2020-10-25 13:11:00 发布