Given a string, determine if it is a palindrome, considering only alphanumeric characters and ignoring cases.
For example,
"A man, a plan, a canal: Panama" is a palindrome.
"race a car" is not a palindrome.
Note:
Have you consider that the string might be empty? This is a good question to ask during an interview.
For the purpose of this problem, we define empty string as valid palindrome.
class Solution {
public:
bool isPalindrome(string s) {
int len = s.size();
if(len <= 1) return true;
std::transform(s.begin(), s.end(), s.begin(), ::tolower);
int front = 0;
int back = len-1;
while(front < back) {
if(!isalnum(s[front]))
++front;
else if(!isalnum(s[back]))
--back;
else {
if(s[front] == s[back]) {
++front;
--back;
}
else
break;
}
}
if(front >= back)
return true;
else
return false;
}
};
本文介绍了一个C++实现的方法,用于检查一个字符串是否为回文,只考虑字母数字字符且忽略大小写。通过前后指针遍历字符串进行比较,并跳过非字母数字字符。
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