1124. Raffle for Weibo Followers (20)-优快云博客

本文链接：https://blog.youkuaiyun.com/lyw_321/article/details/77917417

本文介绍了一个简单的抽奖程序设计案例，该程序用于从微博转发中选取幸运粉丝作为赢家，并考虑了同一用户多次转发的情况，确保每位用户只能获奖一次。

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1124. Raffle for Weibo Followers (20)

时间限制

400 ms

内存限制

65536 kB

代码长度限制

16000 B

判题程序

Standard

作者

CHEN, Yue

John got a full mark on PAT. He was so happy that he decided to hold a raffle（抽奖） for his followers on Weibo -- that is, he would select winners from every N followers who forwarded his post, and give away gifts. Now you are supposed to help him generate the list of winners.

Input Specification:

Each input file contains one test case. For each case, the first line gives three positive integers M (<= 1000), N and S, being the total number of forwards, the skip number of winners, and the index of the first winner (the indices start from 1). Then M lines follow, each gives the nickname (a nonempty string of no more than 20 characters, with no white space or return) of a follower who has forwarded John's post.

Note: it is possible that someone would forward more than once, but no one can win more than once. Hence if the current candidate of a winner has won before, we must skip him/her and consider the next one.

Output Specification:

For each case, print the list of winners in the same order as in the input, each nickname occupies a line. If there is no winner yet, print "Keep going..." instead.

Sample Input 1:

9 3 2
Imgonnawin!
PickMe
PickMeMeMeee
LookHere
Imgonnawin!
TryAgainAgain
TryAgainAgain
Imgonnawin!
TryAgainAgain

Sample Output 1:

PickMe
Imgonnawin!
TryAgainAgain

Sample Input 2:

2 3 5
Imgonnawin!
PickMe

Sample Output 2:

Keep going...

#include<stdio.h>
#include<iostream>
#include<string>
#include<map>
using namespace std;
map<string,int>cou;
int main(){
	int m,n,s,i,flag=0;
	scanf("%d %d %d",&m,&n,&s);
	string name[1010];
	for(i=1;i<=m;i++){
		cin>>name[i];
	}
	for(i=s;i<=m;i=i+n){
		if(cou[name[i]]==0){
			cou[name[i]]=1;
			cout<<name[i]<<endl;
			flag=1;
		}
		else{
			i=i-n+1;
		}
	}
	if(flag==0){
		printf("Keep going...");
	}
}