Java用户列表排序与遍历-优快云博客

本文介绍了一个Java程序，该程序使用集合类对用户列表进行排序并遍历。主要涉及了用户类的定义、排序算法及遍历过程。

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package com.huawei.kong;

import java.util.ArrayList;
import java.util.Collections;
import java.util.Comparator;
import java.util.List;

public class ListSortTest
{

	/**
	 * @param args
	 */
	public static void main(String[] args)
	{
		List<User> userlist = new ArrayList<User>();
		userlist.add(new User("dd", "4"));
		userlist.add(new User("aa", "1"));
		userlist.add(new User("ee", "5"));
		userlist.add(new User("bb", "2"));
		userlist.add(new User("ff", "5"));
		userlist.add(new User("cc", "3"));
		userlist.add(new User("gg", "6"));

		ComparatorUser comparator = new ComparatorUser();
		Collections.sort(userlist, comparator);

		for (int i = 0; i < userlist.size(); i++)
		{
			User user_temp = (User) userlist.get(i);
			System.out.println(user_temp.getAge() + "," + user_temp.getName());
		}

	}

}

class User
{
	String name;
	String age;

	public User(String name, String age)
	{
		this.name = name;
		this.age = age;
	}

	public String getAge()
	{
		return age;
	}

	public void setAge(String age)
	{
		this.age = age;
	}

	public String getName()
	{
		return name;
	}

	public void setName(String name)
	{
		this.name = name;
	}
}

class ComparatorUser implements Comparator<User>
{

	public int compare(User user0, User user1)
	{
		// 首先比较年龄，如果年龄相同，则比较名字
		int flag = user0.getAge().compareTo(user1.getAge());
		if (flag == 0)
		{
			return user0.getName().compareTo(user1.getName());
		}
		else
		{
			return flag;
		}
	}

}

对List排序