[leetcode] Reverse Integer

Reverse Integer

//并没有考虑越界情况

#include<iostream>
using namespace std;

class Solution {
public:
    int reverse(int x) {
    	int result=0;
    	while(x){
    		result=result*10+x%10;
    		x=x/10;
    	}
        return result;
    }
};

int main(int argc, char const *argv[])
{
	/* code */
	Solution so;
	cout<<so.reverse(12345)<<endl;
	cout<<so.reverse(100)<<endl;
	cout<<so.reverse(-100)<<endl;
	return 0;
}