每日一题4.1

每日一题4.1

变态跳台阶

代码实现：

#include <iostream>
using namespace std;
class Solution {
public:
	int jumpFloorII(int number) {
		if (number <= 0)
			return 0;
		if (1 == number)
			return 1;
		return 2 * jumpFloorII(number - 1);
	}
};