HDU1037

1037
Keep on Truckin’
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 14765 Accepted Submission(s): 10144

Problem Description
Boudreaux and Thibodeaux are on the road again …

“Boudreaux, we have to get this shipment of mudbugs to Baton Rouge by tonight!”

“Don’t worry, Thibodeaux, I already checked ahead. There are three underpasses and our 18-wheeler will fit through all of them, so just keep that motor running!”

“We’re not going to make it, I say!”

So, which is it: will there be a very messy accident on Interstate 10, or is Thibodeaux just letting the sound of his own wheels drive him crazy?

Input
Input to this problem will consist of a single data set. The data set will be formatted according to the following description.

The data set will consist of a single line containing 3 numbers, separated by single spaces. Each number represents the height of a single underpass in inches. Each number will be between 0 and 300 inclusive.

Output
There will be exactly one line of output. This line will be:

NO CRASH

if the height of the 18-wheeler is less than the height of each of the underpasses, or:

CRASH X

otherwise, where X is the height of the first underpass in the data set that the 18-wheeler is unable to go under (which means its height is less than or equal to the height of the 18-wheeler).
The height of the 18-wheeler is 168 inches.

Sample Input
180 160 170

Sample Output
CRASH 160

Source
South Central USA 2003

Recommend
We have carefully selected several similar problems for you: 1040 1020 1064 1038 1056


纯英语题,判断输入的值是否<=168,是就撞了

#include<cstdio>
int main()
{
    int a, b, c;
    while (scanf("%d%d%d", &a, &b, &c) != EOF)
    {
        if (a <= 168)
            printf("CRASH %d\n", a);
        else if (b <= 168)
            printf("CRASH %d\n", b);
        else if (c <= 168)
            printf("CRASH %d\n", c);
        else
            printf("NO CRASH\n");
    }
}
评论
添加红包

请填写红包祝福语或标题

红包个数最小为10个

红包金额最低5元

当前余额3.43前往充值 >
需支付:10.00
成就一亿技术人!
领取后你会自动成为博主和红包主的粉丝 规则
hope_wisdom
发出的红包
实付
使用余额支付
点击重新获取
扫码支付
钱包余额 0

抵扣说明:

1.余额是钱包充值的虚拟货币,按照1:1的比例进行支付金额的抵扣。
2.余额无法直接购买下载,可以购买VIP、付费专栏及课程。

余额充值