IP Address
Time Limit: 1000MS | Memory Limit: 30000K | |
Total Submissions: 19126 | Accepted: 11054 |
Description
Suppose you are reading byte streams from any device, representing IP addresses. Your task is to convert a 32 characters long sequence of '1s' and '0s' (bits) to a dotted decimal format. A dotted decimal format for an IP address is form by grouping 8 bits at
a time and converting the binary representation to decimal representation. Any 8 bits is a valid part of an IP address. To convert binary numbers to decimal numbers remember that both are positional numerical systems, where the first 8 positions of the binary
systems are:
27 26 25 24 23 22 21 20 128 64 32 16 8 4 2 1
Input
The input will have a number N (1<=N<=9) in its first line representing the number of streams to convert. N lines will follow.
Output
The output must have N lines with a doted decimal IP address. A dotted decimal IP address is formed by grouping 8 bit at the time and converting the binary representation to decimal representation.
Sample Input
4 00000000000000000000000000000000 00000011100000001111111111111111 11001011100001001110010110000000 01010000000100000000000000000001
Sample Output
0.0.0.0 3.128.255.255 203.132.229.128 80.16.0.1
#include <iostream> #include<cstdio> #include<cstring> #include<algorithm> using namespace std; int a[10]; int main() { ios::sync_with_stdio(false); char s[40]; int flag,n,sum,i,j; while(cin>>n) { while(n--) { cin>>s; flag=1; for( i=0; i<4; i++) { sum=0; for( j=7; j>=0; j--) { sum+=(s[i*8+j]-'0')*(1<<(7-j)); //每8位从低到高; } if(flag) flag=0; else cout<<"."; cout<<sum; if(i==3&&j==-1) { cout<<endl; break; } } } } return 0; }