Django 和AJAX 交互
AJAX:
<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="UTF-8">
<title>AjaxTest</title>
<style>
.success{
color: green;
}
.error{
color: gray;
}
</style>
</head>
<body>
<div>
<h1>Ajex</h1>
<p>Username:<input type="text" id="username"></p>
<p>Password:<input type="password" id ="password"></p>
<p><a onclick="tijiao1();">tijiao</a></p>
<span id="status"></span>
</div>
<script type="text/javascript" src="/static/js/jquery-2.2.4.min.js"></script>
<script>
function tijiao1(){
var user =$('#username').val()
var pwd =$('#password').val()
$.ajax({
url:'/ajax/',
type:'POST',
data:{username:user,password:pwd},
success:function(callback){
var callback_dict = $.parseJSON(callback);
if (callback_dict.status==1002){
$('#status').text('success');
$('#status').removeClass('error').addClass('success');
}else if(callback_dict.status == 1001){
$('#status').text(callback_dict.error);
$('#status').removeClass('success').addClass('error')
}
}
})
}
</script>
</body>
</html>
Django views Code
from django.shortcuts import render,HttpResponse
import json
# Create your views here.
def ajax(request):
if request.method =='POST':
ret={'status':1001,'error':''}
user=request.POST.get('username')
pwd=request.POST.get('password')
print (user,pwd)
if user == 'freeman' and pwd == 'redhat':
ret['status'] = 1002
else:
ret['error']='Username oR password error'
return HttpResponse(json.dumps(ret))
return render(request,'ajax.html')
本文通过一个具体的示例介绍了如何使用Django后端框架与AJAX进行交互。前端部分采用HTML、CSS和JavaScript实现了一个简单的登录表单,当用户提交表单时,通过AJAX发送POST请求到Django后端;后端验证用户名和密码,并返回相应的响应。该示例展示了前端与后端之间的数据交换过程。
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