#include <iostream>
using namespace std;
int main()
{
int n, m, i, j = 0, s = 0, sum = 0, average;
while (cin >> n >> m && n <= 100)
{
for (i = 0; i < n; i++)
{
s += 2;
sum += s;
j++;
if (j == m && i < n - 1)
{
average = sum/m;
printf("%d ", average);
j = 0;
sum = 0;
}
else if (j == m && i == n - 1)
{
average = sum/m;
printf("%d", average);
j = 0;
sum = 0;
}
}
if (n%m == 0)
{
printf("%\n");
s = 0;
}
if (j < m && i > (n/m*m))
{
average = sum/(n%m);
printf("%d\n", average);
j = 0;
sum = 0;
s = 0;
}
}
return 0;
}
HDU ACM 11 2015 偶数求和
最新推荐文章于 2021-05-22 23:44:33 发布