hdoj1004

Let the Balloon Rise

                                                                         Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)

Problem Description

Contest time again! How excited it is to see balloons floating around. But to tell you a secret, the judges' favorite time is guessing the most popular problem. When the contest is over, they will count the balloons of each color and find the result.

This year, they decide to leave this lovely job to you. 

 

Input

Input contains multiple test cases. Each test case starts with a number N (0 < N <= 1000) -- the total number of balloons distributed. The next N lines contain one color each. The color of a balloon is a string of up to 15 lower-case letters.

A test case with N = 0 terminates the input and this test case is not to be processed.

 

Output

For each case, print the color of balloon for the most popular problem on a single line. It is guaranteed that there is a unique solution for each test case.

 

Sample Input

  

   5
green
red
blue
red
red
3
pink
orange
pink
0
  

 

Sample Output

  

   red
pink
  

 

Author

WU, Jiazhi

 

Source

ZJCPC2004

 

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#include<stdio.h>
#include<string.h>

#define M 1000

int N;

char string[15]; //暂时存放气球名称

int max; //最多的那种气球有多少个

int mkind; //数量最多的气球的序号

struct ballon {//气球结构，name表示名称，number表示数量
    char name[15];
    int number;
} ballon[M];

void find(char *string) {
    int i;
    for (i = 0; strcmp(string, ballon[i].name) && ballon[i].number; i++);
    //跳出循环的时候，ballon[i].number==0表示前面没出现过这种气球，strcmp(string,ballon[i].name)==0表示前面出现过这种气球
    if (!ballon[i].number)//如果ballon[i].number==0，表示前面没出现过这种气球，需要在气球数组中添加一个元素
        strcpy(ballon[i].name, string);
    ballon[i].number++;
    if (ballon[i].number > max) {//如果该气球数量大于max，把max更新为这种气球的数量，kind更新为这种气球的序号
        max = ballon[i].number;
        mkind = i;
    }
}

int main(void) {
    while (scanf("%d", &N) && N) {
        memset(ballon, 0, sizeof (ballon));
        max = -1;
        mkind = -1;
        for (int i = 0; i < N; i++) {
            scanf("%s", string);
            find(string);
        }
        printf("%s\n", ballon[mkind].name);
    }
    return 0;
}