N!
Time Limit: 10000/5000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 33698 Accepted Submission(s): 9380
Problem Description
Given an integer N(0 ≤ N ≤ 10000), your task is to calculate N!
Input
One N in one line, process to the end of file.
Output
For each N, output N! in one line.
Sample Input
1 2 3
Sample Output
1 2 6
Author
JGShining(极光炫影)
#include<stdio.h>
#include<string.h>
int number[100001];
int main(void) {
int n;
while (scanf("%d", &n) != EOF) {
memset(number, 0, sizeof (number));
number[0] = 1;
int digit=0;//最高位
for (int i = 2; i <= n; i++) {
int c = 0;
for (int j = 0; j <=digit; j++) {
int s = number[j] * i + c;
number[j] = s % 10;
c = s / 10;
}
while(c){//进位
number[++digit]=c%10;
c/=10;
}
}
for(int i=digit;i>=0;i--)
printf("%d",number[i]);
printf("\n");
}
return 0;
}