随便5个字-优快云博客

原创 Spring的bean中直接调用成员变量出现nullpointexception的解决方法

前提：Spring管理的前提下，在构造方法中调用成员变量。解决方法：在bean中再实现一个接口：InitializingBean然后在afterPropertiesSet方法里去调用成员变量。

2013-11-30 11:58:17 1097

原创 JAVA编程思想第四版-多线程的练习答案之练习20

package exercise.exercise20;public class LiftOff implements Runnable { protected int countDown = 10; private static int taskCount = 0; private final int id = taskCount++; public LiftOff() {

2013-11-12 23:00:43 854

原创 JAVA编程思想第四版-多线程的练习答案之练习19

package exercise.exercise19;import java.util.ArrayList;import java.util.List;import java.util.Random;import java.util.concurrent.ExecutorService;import java.util.concurrent.Executors;import jav

2013-11-12 22:59:36 993

原创自增自减的习题

背景：最近面试，遇到了非常基础的题目。可惜做的不是太好了。恶补1天，找了一些习题来练手。先贴出来：// 第一题。难度：1 int count = 0; for (int i = 0; i < 10; i++) { count++; } System.out.println("The eventual value of count is:" + count + "

2013-11-08 12:08:40 1652

原创 JAVA编程思想第四版-多线程的练习答案之练习16

练习16和练习15的要求一样。只不过同步的方式要用Lock。代码如下：package exercise.exercise16;public interface ThrillingInter { void aInc(); void bInc(); void cInc();}package exercise.exercise16;public class Ma

2013-10-31 22:03:11 924

原创 JAVA编程思想第四版-多线程的练习答案之练习14

package exercise.exercise14;import java.util.Timer;import java.util.TimerTask;import java.util.concurrent.ExecutorService;import java.util.concurrent.Executors;import java.util.concurrent.atomic

2013-10-28 10:20:42 844

原创排序算法-插入排序

package insert;import util.ArrayUtil;public class InsertSort { public static void main(String[] args) { /** * 判断索引为j和索引为j-k的值，如果索引为j的值大于索引为j-k的值，就不用换为位置，直接退出内循环，否则就交换位置，直到j-k为0。 * *

2013-10-28 01:19:43 587

原创 JAVA编程思想第四版-多线程的练习答案之练习13

package exercise.exercise13;public class SerialNumberGenerator { private static volatile int serialNumber = 0; public static int nextSerialNumber(){ return serialNumber++; }}package exercise

2013-10-28 01:12:06 792

原创 JAVA编程思想第四版-多线程的练习答案之练习12

package exercise.exercise12;import java.util.concurrent.ExecutorService;import java.util.concurrent.Executors;public class AtomicityTest implements Runnable { private int i = 0; public sy

2013-10-28 00:59:11 920

原创 JAVA编程思想第四版-多线程的练习答案之练习11

exercise.exercise11.Number.JAVApackage exercise.exercise11;public class Number{ private int x; private int y; public Number(int x, int y) { this.x = x; this.y = y; } public Number()

2013-10-24 22:34:51 706

原创 JAVA编程思想第四版-多线程的练习答案之练习8

package exercise.exercise08;public class SimpleThread extends Thread { private int countDown = 5; private static int threadCount = 0; public SimpleThread() { super(Integer.toString(++threadCo

2013-10-21 00:44:39 1057

原创 JAVA编程思想第四版-多线程的练习答案之练习7

package exercise.exercise07;public class Daemons{public static void main(String[] args) throws InterruptedException{Thread d = new Thread(new Daemon());d.setDaemon(true);d.start();

2013-10-21 00:43:28 1067

原创 JAVA编程思想第四版-多线程的练习答案之练习6

package exercise.exercise06;import java.util.Random;public class RandomSleepTask implements Runnable { @Override public void run() { int randomNum = new Random().nextInt(10); try { synch

2013-10-21 00:41:51 856

原创 JAVA编程思想第四版-多线程的练习答案之练习5

package exercise.exercise05;public interface Generator { T next();}package exercise.exercise05;import java.util.ArrayList;import java.util.Arrays;import java.util.concurrent.Callable;import

2013-10-21 00:37:40 889

转载 JAVA编程思想第四版-多线程的练习答案之练习2

package exercise.exercise02;public class Fibonacci implements Runnable { int fibonacciCount; public Fibonacci(int fibonacciCount){ this.fibonacciCount = fibonacciCount; } @Override publi

2013-10-21 00:31:11 1207

原创 JAVA编程思想第四版-多线程的练习答案之练习1

package exercise.exercise01;public class Demo1_656 implements Runnable { public Demo1_656(){ System.out.println(" prepared start ..."); } @Override public void run() { for (int i = 0; i <

2013-10-21 00:27:22 889

原创 JAVA编程思想第四版-多线程的练习答案之练习10

package exercise.exercise10;import java.util.ArrayList;import java.util.concurrent.Callable;import java.util.concurrent.ExecutionException;import java.util.concurrent.ExecutorService;import java

2013-10-21 00:19:30 1426