Given a binary tree containing digits from 0-9 only,
each root-to-leaf path could represent a number.
An example is the root-to-leaf path 1->2->3 which
represents the number 123.
Find the total sum of all root-to-leaf numbers.
For example,
1 / \ 2 3
The root-to-leaf path 1->2 represents
the number 12.
The root-to-leaf path 1->3 represents
the number 13.
Return the sum = 12 + 13 = 25.
class Solution {
public:
int sumNumbers(TreeNode *root) {
// Start typing your C/C++ solution below
// DO NOT write int main() function
if(!root)return 0;
int itermedia=0,sum=0;
DFS(root,itermedia,sum);
return sum;
}
void DFS(TreeNode *root, int& itermedia, int& sum){
itermedia=itermedia*10+root->val;
if(!root->left && !root->right){
sum+=itermedia;
itermedia/=10;
return;
}
if(root->left)
DFS(root->left,itermedia,sum);
if(root->right)
DFS(root->right,itermedia,sum);
itermedia/=10;
}
};
402



被折叠的 条评论
为什么被折叠?



