llz12345679的博客

原创 基于Python求解1+(1+2)+(1+2+3)+...+(1+2+3+...+n)之和

n = eval(input("请输入n值："))sum = 0'解法一，采用两重迭代'for i in range(1 , n+1): for j in range(1 , i+1): sum += jprint("1+(1+2)+(1+2+3)+...+(1+2+3+...+n)求和为：" + str(sum))'解法二，采用一重迭代'for i in range(1,n+1): sum += i*(i+1)/2print("1+(1+2)+(1+2+...