hdu 1596(SPFA)

本文介绍了使用SPFA算法解决图中单源最短路径问题的过程,并通过具体实例展示了算法的实现细节。与Dijkstra算法相比,SPFA算法在某些情况下能够提供更好的性能。

本题想用spfa算法实现,昨天看了很长时间没弄个一清二白,╮(╯▽╰)╭,今天早晨趁着精神好,赶紧看下,还真弄出来了,其实还是和dijkstra相差无几,只是昨个儿下午太不给力了,看来状态不好时真不能搞算法,不然越搞越昏,赔了时间又折煞自己的心情……

http://acm.hdu.edu.cn/showproblem.php?pid=1596

#include <iostream>
#include<cstdio>
#include<string.h>
using namespace std;
int n,m,st,ed,front,rear;
double mat[1005][1005],dis[1005];
int v[1005],q[1000001];
void Spfa()
{
	int p;
	while(front<rear)//模拟栈,直到栈为空
	{
		p=q[front++];
		v[p]=0;
		for(int i=0;i<n;i++)
		{
			if(mat[p][i]==0||p==i)
				continue;
			if(dis[p]*mat[p][i]>dis[i])
			{
				dis[i]=dis[p]*mat[p][i];
				if(!v[i])
				{
					q[rear++]=i;
					v[i]=1;
				}
			}
		}
	}
}
int main()
{
	
	while(scanf("%d",&n)!=EOF)
	{
		for(int i=0;i<n;i++)
			for(int j=0;j<n;j++)
				scanf("%lf",&mat[i][j]);
		scanf("%d",&m);
		while(m--)
		{
			scanf("%d%d",&st,&ed);
			memset(v,0,sizeof(v));
			memset(dis,0,sizeof(dis));
			v[st-1]=dis[st-1]=1;
			front=0;
			rear=1;
			q[front]=st-1;
			Spfa();
			if(dis[ed-1]!=0)
				printf("%.3lf\n",dis[ed-1]);
			else
				puts("What a pity!");
		}
	}
}


以下是hdu4310的Java解法: ```java import java.util.*; import java.io.*; public class Main { static int MAXN = 100010; static int MAXM = 200010; static int INF = 0x3f3f3f3f; static int n, m, s, t, cnt; static int[] head = new int[MAXN]; static int[] dis = new int[MAXN]; static boolean[] vis = new boolean[MAXN]; static int[] pre = new int[MAXN]; static int[] cur = new int[MAXN]; static class Edge { int to, next, cap, flow, cost; public Edge(int to, int next, int cap, int flow, int cost) { this.to = to; this.next = next; this.cap = cap; this.flow = flow; this.cost = cost; } } static Edge[] edge = new Edge[MAXM]; static void addEdge(int u, int v, int cap, int flow, int cost) { edge[cnt] = new Edge(v, head[u], cap, flow, cost); head[u] = cnt++; edge[cnt] = new Edge(u, head[v], 0, 0, -cost); head[v] = cnt++; } static boolean spfa() { Arrays.fill(dis, INF); Arrays.fill(vis, false); Queue<Integer> q = new LinkedList<>(); q.offer(s); dis[s] = 0; vis[s] = true; while (!q.isEmpty()) { int u = q.poll(); vis[u] = false; for (int i = head[u]; i != -1; i = edge[i].next) { int v = edge[i].to; if (edge[i].cap > edge[i].flow && dis[v] > dis[u] + edge[i].cost) { dis[v] = dis[u] + edge[i].cost; pre[v] = u; cur[v] = i; if (!vis[v]) { vis[v] = true; q.offer(v); } } } } return dis[t] != INF; } static int[] MCMF(int s, int t) { int flow = 0, cost = 0; while (spfa()) { int f = INF; for (int u = t; u != s; u = pre[u]) { f = Math.min(f, edge[cur[u]].cap - edge[cur[u]].flow); } for (int u = t; u != s; u = pre[u]) { edge[cur[u]].flow += f; edge[cur[u] ^ 1].flow -= f; cost += edge[cur[u]].cost * f; } flow += f; } return new int[]{flow, cost}; } public static void main(String[] args) { Scanner in = new Scanner(new BufferedReader(new InputStreamReader(System.in))); int T = in.nextInt(); for (int cas = 1; cas <= T; cas++) { n = in.nextInt(); m = in.nextInt(); s = 0; t = n + m + 1; cnt = 0; Arrays.fill(head, -1); for (int i = 1; i <= n; i++) { int c = in.nextInt(); addEdge(s, i, c, 0, 0); } for (int i = 1; i <= m; i++) { int c = in.nextInt(); addEdge(i + n, t, c, 0, 0); } for (int i = 1; i <= n; i++) { for (int j = 1; j <= m; j++) { int c = in.nextInt(); addEdge(i, j + n, INF, 0, c); } } int[] ans = MCMF(s, t); System.out.printf("Case #%d: %d\n", cas, ans[1]); } } } ```
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