1001. A+B Format (20)-PAT甲级真题

原创已于 2023-11-09 16:43:43 修改 · 9.1k 阅读

23 ·

CC 4.0 BY-SA版权

文章标签：

#PAT #算法

于 2016-07-21 19:25:52 首次发布

本篇博客介绍了一个简单的程序设计问题，即计算两个整数A和B的和，并将结果以每三位数字用逗号分隔的形式输出。通过将结果转换为字符串并遍历每个字符，在适当的位置插入逗号来实现。

Calculate a + b and output the sum in standard format — that is, the digits must be separated into groups of three by commas (unless there are less than four digits).

Input

Each input file contains one test case. Each case contains a pair of integers a and b where -1000000 <= a, b <= 1000000. The numbers are separated by a space.

Output

For each test case, you should output the sum of a and b in one line. The sum must be written in the standard format.

Sample Input

-1000000 9

Sample Output

-999,991

题目大意：计算A+B的和，然后以每三位加一个"."的格式输出～

分析：把a+b的和转为字符串s～除了第一位是负号的情况，只要当前位的下标i满足(i + 1) % 3 == len % 3并且i不是最后一位，就在逐位输出的时候在该位输出后的后面加上一个逗号～

#include <iostream>
using namespace std;
int main() {
    int a, b;
    cin >> a >> b;
    string s = to_string(a + b);
    int len = s.length();
    for (int i = 0; i < len; i++) {
        cout << s[i];
        if (s[i] == '-') continue;
        if ((i + 1) % 3 == len % 3 && i != len - 1) cout << ",";
    }
    return 0;
}