import java.util.ArrayList;
import java.util.Arrays;
import java.util.Scanner;
class TreeNode {
int val;
TreeNode left;
TreeNode right;
TreeNode(int val) {
this.val = val;
left = null;
right = null;
}
}
/**
* BST,a节点左边的节点value都【小于】a,右边的节点【大于等于】a
* a先序数组,b中序数组
* 在BST(中序从小到大)中,当存在有重复元素的时候,在中序中应该第一个出现a[0]的位置
* 而在BST镜像树中(中序从大到小),在中序中应该最后一个出现a[0]的位置
*
* 故:在createTree和createTree1中,遍历b的顺序不同
* for (i = bf; i <= bl; i++) 和for (i = bl; i >= bf; i--)区别
*
* 创建日期:2014年10月10日
* @author chenshanfu
*/
public class Main {
private static ArrayList<Integer> resultList = new ArrayList<Integer>();
public static void postorderPrint(TreeNode root) {
if (root != null) {
if (root.left != null)
postorderPrint(root.left);
if (root.right != null)
postorderPrint(root.right);
resultList.add(root.val);
}
}
// 从小到大
public static boolean check(int[] a, int[] b, int af, int al, int bf, int bl) {
int i, nextlen;
if (al < af)
return true;
for (i = bf; i <= bl; i++) {
if (b[i] == a[af]) {
break;
}
}
nextlen = i - bf;
for (int j = af + 1; j <= al; j++) {
if ((j <= af + nextlen && a[j] >= b[i])
|| (j >= af + nextlen + 1 && a[j] < b[i])) {
/*
* System.err.println("i="+i); System.err.println("j="+j);
*/
return false;
}
}
return check(a, b, af + 1, af + nextlen, bf, bf + nextlen - 1)
&& check(a, b, af + nextlen + 1, al, bf + nextlen + 1, bl);
}
// 从大到小
public static boolean check1(int[] a, int[] b, int af, int al, int bf,
int bl) {
int i, nextlen;
if (al < af)
return true;
for (i = bl; i >= bf; i--) {
if (b[i] == a[af]) {
break;
}
}
nextlen = i - bf;
for (int j = af + 1; j <= al; j++) {
if ((j <= af + nextlen && a[j] < b[i])
|| (j >= af + nextlen + 1 && a[j] >= b[i])) {
return false;
}
}
return check1(a, b, af + 1, af + nextlen, bf, bf + nextlen - 1)
&& check1(a, b, af + nextlen + 1, al, bf + nextlen + 1, bl);
}
//从小到大创建树
/**
*
*
* @param a先序
* @param b中序
* @param af先序开始位置(包含)
* @param al先序结束位置(包含)
* @param bf中序开始位置(包含)
* @param bl中序结束位置(包含)
* @return
* 创建日期:2014年10月10日
* 修改说明:
* @author chenshanfu
*/
public static TreeNode createTree(int[] a, int[] b, int af, int al, int bf,
int bl) {
int i, nextlen;
if (al < af)
return null;
TreeNode root = new TreeNode(a[af]);
for (i = bf; i <= bl; i++) {
if (b[i] == a[af]) {
break;
}
}
nextlen = i - bf;
root.left = createTree(a, b, af + 1, af + nextlen, bf, bf + nextlen - 1);
root.right = createTree(a, b, af + nextlen + 1, al, bf + nextlen + 1,
bl);
return root;
}
//从大到小创建树
public static TreeNode createTree1(int[] a, int[] b, int af, int al, int bf,
int bl) {
int i, nextlen;
if (al < af)
return null;
TreeNode root = new TreeNode(a[af]);
for (i = bl; i >= bf; i--) {
if (b[i] == a[af]) {
break;
}
}
nextlen = i - bf;
root.left = createTree(a, b, af + 1, af + nextlen, bf, bf + nextlen - 1);
root.right = createTree(a, b, af + nextlen + 1, al, bf + nextlen + 1,
bl);
return root;
}
public static void main(String[] args) {
// TODO Auto-generated method stub
Scanner input = new Scanner(System.in);
int n = input.nextInt();
int[] a = new int[n];// preorder
int[] b = new int[n];// inorder 从小到大
int[] c = new int[n];// inorder 从大到小
for (int i = 0; i < n; i++) {
a[i] = input.nextInt();
}
for (int i = 0; i < n; i++) {
b[i] = a[i];
}
Arrays.sort(b);
for (int i = 0; i < n; i++) {
c[i] = b[n - 1 - i];
}
/*System.err.println(check(a, b, 0, n - 1, 0, n - 1));
System.err.println(check1(a, c, 0, n - 1, 0, n - 1));*/
if (check(a, b, 0, n - 1, 0, n - 1)) {
TreeNode rootNode = null;
rootNode = createTree(a, b, 0, n - 1, 0, n - 1);
postorderPrint(rootNode);
System.out.println("YES");
for (int i = 0; i < resultList.size(); i++) {
if (i != resultList.size() - 1)
System.out.print(resultList.get(i) + " ");
else
System.out.println(resultList.get(i));
}
} else if (check1(a, c, 0, n - 1, 0, n - 1)) {
TreeNode rootNode = null;
rootNode = createTree1(a, c, 0, n - 1, 0, n - 1);
postorderPrint(rootNode);
System.out.println("YES");
for (int i = 0; i < resultList.size(); i++) {
if (i != resultList.size() - 1)
System.out.print(resultList.get(i) + " ");
else
System.out.println(resultList.get(i));
}
} else {
System.out.println("NO");
}
}
}
【PAT】1043. Is It a Binary Search Tree (25)
最新推荐文章于 2022-09-22 18:02:29 发布