2014年AP生物考试真题解析

这篇博客通过2014年AP生物考试的一个真题,讲解了如何分析家谱图并运用孟德尔定律计算遗传病的概率。重点在于识别性连锁遗传疾病(因所有受影响的个体都是男性)和判断其为隐性遗传(由于父母未受影响但子代中出现病症)。解题过程包括确定疾病基因型、绘制配子组合矩阵以及计算儿子患病的可能性。

cc7053a10bc8267fc48fe0b292f242f8.png(题目选自2014年AP生物真题; MC24)

文字版解析如下:

答案:B

考点:

1. Pedigree Analysis

2. Applying Punnett Squares to Calculate Probabilities

162ee1fd86566cd076e21423b98a707f.png

解题思路:

1. Determine the genotype of the affected male in the third generation

2. Use a Punnett Square and cross the affected male with a carrier female

3. Calculate probability of son being affected with the disorder

解题步骤:

- Determine if the disorder is autosomal or sex-linked

o There is a disproportionate number of affected males vs. females. All of the individuals with the disorder (shaded symbols) are males. There are no affected females. This indicates a sex-linked disorder.

- Determine if the disorder is dominant or recessive

o The parents in generation I do not have the disorder, but 2 of their sons in generation II have the disorder. When affected individuals have unaffected parents, it indicates a recessive disorder.

评论
添加红包

请填写红包祝福语或标题

红包个数最小为10个

红包金额最低5元

当前余额3.43前往充值 >
需支付:10.00
成就一亿技术人!
领取后你会自动成为博主和红包主的粉丝 规则
hope_wisdom
发出的红包
实付
使用余额支付
点击重新获取
扫码支付
钱包余额 0

抵扣说明:

1.余额是钱包充值的虚拟货币,按照1:1的比例进行支付金额的抵扣。
2.余额无法直接购买下载,可以购买VIP、付费专栏及课程。

余额充值