--聚合函数max min avg sum count
select max(english) from score
select min(english) from score
--null值不参加avg的运算,所以当english有null值时,算平均值会有问题
select avg(english) from score
select sum(english)/count(*) from score
select sum(english) from score
select count(sId) from student
select count(*) from student where sSex='女'
select max(english) as '最大值',min(english) as '最小值',avg(english) as '平均值'
from score
select max(sBirthday),min(sBirthday) from student --查询日期的最大值,最小值