Spring声明式事务学习

快过年了，没什么事情，看了一下spring2.0中的声明式的事务处理，自己做了一个小例子，是JTA方式的。
dataAccessContext-jta.xml
[code]<?xml version="1.0" encoding="UTF-8"?>

<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:jee="http://www.springframework.org/schema/jee"
xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-2.0.xsd
http://www.springframework.org/schema/jee http://www.springframework.org/schema/jee/spring-jee-2.0.xsd">


<jee:jndi-lookup id="DataSource" jndi-name="java:comp/env/jdbc/DataSource"/>

<jee:jndi-lookup id="DataSource2" jndi-name="java:comp/env/jdbc/DataSource2"/>

<bean id="transactionManager" class="org.springframework.transaction.jta.JtaTransactionManager"/>

<bean id="UserDao" class="dao.UserDaoImpl">
<property name="ds" ref="DataSource"/>
<property name="ds2" ref="DataSource2"/>
</bean>


</beans>[/code]

applicationContext.xml

[code]<?xml version="1.0" encoding="UTF-8"?>

<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:aop="http://www.springframework.org/schema/aop"
xmlns:tx="http://www.springframework.org/schema/tx"
xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-2.0.xsd
http://www.springframework.org/schema/aop http://www.springframework.org/schema/aop/spring-aop-2.0.xsd
http://www.springframework.org/schema/tx http://www.springframework.org/schema/tx/spring-tx-2.0.xsd">


<aop:config>
<aop:advisor pointcut="execution(* *..UserDao.*(..))" advice-ref="txAdvice"/>
</aop:config>

<tx:advice id="txAdvice" transaction-manager="transactionManager">
<tx:attributes>
<tx:method name="insert*" rollback-for="java.sql.SQLException"/>
<tx:method name="update*"/>
<tx:method name="*" read-only="true"/>
</tx:attributes>
</tx:advice>

</beans>
[/code]