HDU1164:Eddy's research I

本文介绍了一个用于将整数分解为其素数因子的程序。该程序首先生成一个素数列表,然后利用这些素数来分解输入的整数。输入为一个整数,输出则是该整数的素数因子分解形式。
Problem Description
Eddy's interest is very extensive, recently he is interested in prime number. Eddy discover the all number owned can be divided into the multiply of prime number, but he can't write program, so Eddy has to ask intelligent you to help him, he asks you to write a program which can do the number to divided into the multiply of prime number factor .

 

Input
The input will contain a number 1 < x<= 65535 per line representing the number of elements of the set.
 

Output
You have to print a line in the output for each entry with the answer to the previous question.
 

Sample Input
11 9412
 

Sample Output
11 2*2*13*181
 


 

#include <stdio.h>
#include <string.h>

int prime[70000];

void sushu(void)
{
    int i,j;
    memset(prime,1,sizeof(prime));
    for(i = 2; i<70000; i++)
    {
        if(prime[i])
        {
            for(j = i+i; j<70000; j+=i)
            {
                prime[j] = 0;
            }
        }
    }
}

int main()
{
    int n,i;
    sushu();
    while(~scanf("%d",&n))
    {
        if(prime[n])
        {
            printf("%d\n",n);
            continue;
        }
        int flag = 1;
        for(i = 2; i<=n; i++)
        {
            while(n%i == 0)
            {
                if(flag)
                {
                    printf("%d",i);
                    flag = 0;
                }
                else
                    printf("*%d",i);
                n = n/i;
            }
        }
        printf("\n");
    }

    return 0;
}


 

 

评论
成就一亿技术人!
拼手气红包6.0元
还能输入1000个字符
 
红包 添加红包
表情包 插入表情
 条评论被折叠 查看
添加红包

请填写红包祝福语或标题

红包个数最小为10个

红包金额最低5元

当前余额3.43前往充值 >
需支付:10.00
成就一亿技术人!
领取后你会自动成为博主和红包主的粉丝 规则
hope_wisdom
发出的红包
实付
使用余额支付
点击重新获取
扫码支付
钱包余额 0

抵扣说明:

1.余额是钱包充值的虚拟货币,按照1:1的比例进行支付金额的抵扣。
2.余额无法直接购买下载,可以购买VIP、付费专栏及课程。

余额充值