python人机对战井字棋欢迎来挑战（难度极高）

最新推荐文章于 2025-03-26 22:40:39 发布

lianhongyao

最新推荐文章于 2025-03-26 22:40:39 发布

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文章标签： python pygame 开发语言

本文链接：https://blog.youkuaiyun.com/lianhongyao/article/details/126539325

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这篇博客介绍了如何使用Python的pygame库开发一款难度极高的井字棋游戏，玩家可以与计算机进行对战。首先，需要通过pip安装pygame库，然后详细解析了源码的实现过程。

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1.要安装的库

按住win+r输入cmd 回车确定

再输入 pip install pygame 下载pygame

2.源码

import pygame
import sys
import random
import time

# 设置窗口
pygame.init()
time_clock = pygame.time.Clock()
screen = pygame.display.set_mode((900, 900))
pygame.display.set_caption('双人对战井字棋')

# 颜色
black = [0, 0, 0]
white = [255, 255, 255]
red = [255, 0, 0]
blue = [0, 0, 255]
# 下棋坐标
chess_pos = []
j = 0
chess_pos1 = []
# 场上每个格子是否有棋
lattice = [0, 0, 0,
           0, 0, 0,
           0, 0, 0]
# 轮哪一方下棋
play_chess = 0
first = 0
# 赢的项
win_term = [[0, 1, 2], [3, 4, 5], [6, 7, 8], [0, 3, 6], [1, 4, 7], [2, 5, 8], [0, 4, 8], [2, 4, 6]]

# 循环
while True:
    # 按键判断
    for event in pygame.event.get():
        if event.type == pygame.QUIT:
            pygame.quit()
            sys.exit()

    # 画
    screen.fill(white)
    # 圈
    for i in chess_pos:
        pygame.draw.circle(screen, red, [i[0] + 150, i[1] + 150], 120, 5)
    # 叉
    for i in chess_pos1:
        pygame.draw.line(screen, blue, [i[0] + 30, i[1] + 30], [i[0] + 270, i[1] + 270], 5)
        pygame.draw.line(screen, blue, [i[0] + 270, i[1] + 30], [i[0] + 30, i[1] + 270], 5)
    # 网格
    for i in range(1, 3):
        pygame.draw.line(screen, black, [i * 300, 0], [i * 300, 900])
    for i in range(1, 3):
        pygame.draw.line(screen, black, [0, i * 300], [900, i * 300])
    pygame.display.flip()

    # 鼠标信息
    pos = pygame.mouse.get_pos()
    pre = pygame.mouse.get_pressed()
    # 下棋
    if play_chess == 0:
        first = random.randrange(0, 3)
        if first == 1:
            print("机器先下")
        else:
            print("你先下")
        play_chess = first
    elif play_chess == 1:
        print("轮机器下了")
        yn = False
        j += 1
        for i in win_term:
            x = [lattice[i[1]], lattice[i[2]], lattice[i[0]]]
            if lattice[i[0]] == 2 and lattice[i[1]] == 2 and not yn:
                if lattice[i[2]] == 0:
                    lattice[i[2]] = 1
                    if i[2] == 0:
                        chess_pos.append([0, 600])
                        yn = True
                    elif i[2] == 1:
                        chess_pos.append([300, 600])