select a.DESC2 as name, a.PARENTCODE as code from m_org a inner join (
select au.PARENTCODE from
(select code,PARENTCODE,CODEID from m_org ) au,
(select @sid:='007000075000') pd
where FIND_IN_SET(code,@sid)>0
and `PARENTCODE`!='0'
and @sid:=concat(@sid,',',PARENTCODE)
) b on a.CODE = b.PARENTCODE;
记录一下MySQL 树形数据的无限递归查询
最新推荐文章于 2024-09-05 09:02:28 发布