解析XML - thoughtworks

thoughtworks简介

thoughtworks是解析XML的工具，此工具只需要根据XML的结构创建相应的Java Bean即可，不需要在代码中指定各元素的层次结构

使用

pom.xml中引入依赖包

<dependency>
	<groupId>com.thoughtworks.xstream</groupId>
	<artifactId>xstream</artifactId>
	<version>1.4.11.1</version>
	<type>jar</type>
</dependency>

Person.xml

<?xml version="1.0" encoding="UTF-8"?>
<person>
	<name>lgc</name>
	<address>
		<province>河南省</province>
		<city>洛阳市</city>
	</address>
</person>

根据上面Person.xml的结构写Java Bean文件，因为XML中address还包含子元素，所以address也要作为一个Java Bean

Address.java

package cn.lgc.study.xml.parse.entity;

/**
 * 住址
 * @author 64630
 *
 */
public class Address {
	/** 省份 */
	private String province;
	/** 城市 */
	private String city;
	public String getProvince() {
		return province;
	}
	public void setProvince(String province) {
		this.province = province;
	}
	public String getCity() {
		return city;
	}
	public void setCity(String city) {
		this.city = city;
	}
	@Override
	public String toString() {
		return "Address [province=" + province + ", city=" + city + "]";
	}

}

Person.java

package cn.lgc.study.xml.parse.entity;

public class Person {
	private String name;
	private Address address;
	public String getName() {
		return name;
	}
	public void setName(String name) {
		this.name = name;
	}
	public Address getAddress() {
		return address;
	}
	public void setAddress(Address address) {
		this.address = address;
	}
	@Override
	public String toString() {
		return "Person [name=" + name + ", address=" + address + "]";
	}

}

解析XML测试一下

public void parseSimple() {
	String xmlFileNmae = "Person.xml";
	InputStream ins = ClassLoader.getSystemResourceAsStream(xmlFileNmae);
	XStream xstream = new XStream(new StaxDriver());
	xstream.alias("person", Person.class);	// 指定XML根节点的节点名和对应的java Bean
	Class<?>[] classes = new Class[] { Address.class};	// 允许的类型集合
	XStream.setupDefaultSecurity(xstream);	//注释掉不影响解析
	xstream.allowTypes(classes);			// 允许的类型
	Person person = (Person) xstream.fromXML(ins);
	System.out.println(person);
}

输出结果

Person [name=lgc, address=Address [province=河南省, city=洛阳市]]

解析带重复节点的XML

假设有下面XML文件，root元素中包含多个重复节点
PersonGroup.xml

<?xml version="1.0" encoding="UTF-8"?>
<!-- 包含了一组person元素 -->
<group>
	<person>
		<name>lgc</name>
		<address>
			<province>河南省</province>
			<city>洛阳市</city>
		</address>
	</person>
	<person>
		<name>zds</name>
		<address>
			<province>上海</province>
			<city>浦东新区</city>
		</address>
	</person>
</group>

因为是group元素包含了多个person元素，所以还需要新建一个Group.java文件

解析时只需要加上下面这句话就可以解析重复节点
xstream.addImplicitCollection(Group.class, “person”, Person.class);

• 第一个参数：包含重复节点的Java Bean类型
• 第二个参数：xml中重复的节点名
• 第三个参数：重复节点对应的Java Bean类型

Group.java

package cn.lgc.study.xml.parse.entity;

import java.util.List;

/**
 * 包含了一组person的对象
 * @author 64630
 *
 */
public class Group {
	private List<Person> person;	//属性名一定要和xml中的节点名保持一致

	public List<Person> getPerson() {
		return person;
	}

	public void setPerson(List<Person> person) {
		this.person = person;
	}

	@Override
	public String toString() {
		return "Group [person=" + person + "]";
	}

}

测试代码

public void parseRepeatItem() {
	String xmlFileNmae = "PersonGroup.xml";
	InputStream ins = ClassLoader.getSystemResourceAsStream(xmlFileNmae);
	XStream xstream = new XStream(new StaxDriver());
	xstream.alias("group", Group.class);
	Class<?>[] classes = new Class[] { Group.class};
	xstream.allowTypes(classes);
	xstream.addImplicitCollection(Group.class, "person", Person.class);	//加上这个就可以解析重复元素
	Group group = (Group) xstream.fromXML(ins);
	System.out.println(group);
}