Convert QWERTY to Dvorak

G - Convert QWERTY to Dvorak
Time Limit:2000MS     Memory Limit:65536KB     64bit IO Format:%lld & %llu
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Description
Edward, a poor copy typist, is a user of the Dvorak Layout. But now he has only a QWERTY Keyboard with a broken Caps Lock key, so Edward never presses the broken Caps Lock key. Luckily, all the other keys on the QWERTY keyboard work well. Every day, he has a lot of documents to type. Thus he needs a converter to translate QWERTY into Dvorak. Can you help him?


The QWERTY Layout and the Dvorak Layout are in the following:


Qwerty Layout
The QWERTY Layout
Dvorak Layout
The Dvorak Layout
Input
A QWERTY document Edward typed. The document has no more than 100 kibibytes. And there are no invalid characters in the document.


Output
The Dvorak document.


Sample Input
Jgw Gqm Andpw a H.soav Patsfk f;doe
Nfk Gq.d slpt a X,dokt vdtnsaohe
Kjd yspps,glu pgld; aod yso kd;kgluZ
1234567890
`~!@#$%^&*()}"']_+-=ZQqWEwe{[\|
ANIHDYf.,bt/
ABCDEFuvwxyz

Sample Output

Hi, I'm Abel, a Dvorak Layout user.

But I've only a Qwerty keyboard.
The following lines are for testing:
1234567890
`~!@#$%^&*()+_-={}[]:"'<>,.?/\|
ABCDEFuvwxyz

AXJE>Ugk,qf;

100 kibibytes是100*1024个单位；；用gets的话字符内存要开得大一些深受其害，，

代码1：

#include<cstdio>
#include<cstring>
#include<algorithm> 
using namespace std;
int main()
{
	char ch1[70]={"_-+=QWERTYUIOP{}qwertyuiop[]SDFGHJKL:\"sdfghjkl;'ZXCVBN<>?zxcvbnm,./"};
	char ch2[70]={"{[}]\"<>PYFGCRL?+',.pyfgcrl/=OEUIDHTNS_oeuidhtns-:QJKXBWVZ;qjkxbmwvz"};
	char ch[120];
	int shu[120];
	int n;
	char a;
	while (~scanf("%c",&a))
	{
		if (a=='\n') printf("\n");
		else
		{
			int tt=1;
			for (int j=0;j<70;j++)
		    {
			    if (a==ch1[j])
			    {
			    	tt=0;
				    printf("%c",ch2[j]);
				    break;
			    }
		    }
		    if (tt)
		    printf("%c",a);
		}
	}
	return 0;
}

代码2：

#include<cstdio>
#include<cstring>
#include<algorithm> 
using namespace std;
int main()
{
	char ch1[70]={"_-+=QWERTYUIOP{}qwertyuiop[]SDFGHJKL:\"sdfghjkl;'ZXCVBN<>?zxcvbnm,./"};
	char ch2[70]={"{[}]\"<>PYFGCRL?+',.pyfgcrl/=OEUIDHTNS_oeuidhtns-:QJKXBWVZ;qjkxbmwvz"};
	char ch[100*1205];
	int shu[100*1205];
	int n;
	while (gets(ch))
	{
		int chang=strlen(ch);
		for (int i=0;i<chang;i++)
		{
			int tt=1;
			for (int j=0;j<70;j++)
		    {
			    if (ch[i]==ch1[j])
			    {
			    	tt=0;
				    shu[i]=j;
				    break;
			    }
		    }
		    if (tt)
		    printf("%c",ch[i]);
		    else
		    printf("%c",ch2[shu[i]]);
	    }
		printf("\n");
	}
	return 0;
}